What is area 3x, 3/4 x,70-x^2 ?

The answer to area 3x, 3/4 x,70-x^2 is 20727/128

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area 3x, 3/4 x,70-x^2

area

3 x, \frac{3}{4} x, 70 - x^{2}

\frac{20727}{128}

Decimal Notation

161.92968 \dots

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

3 x = \frac{3}{4} x : x = 0

3 x = 70 - x^{2} : x = - 10, x = 7

\frac{3}{4} x = 70 - x^{2} : x = - \frac{35}{4}, x = 8

= \int_{- 10}^{- \frac{35}{4}} ∣ f_{1} (x) - f_{3} (x) ∣ d x + \int_{- \frac{35}{4}}^{0} ∣ f_{2} (x) - f_{1} (x) ∣ d x + \int_{0}^{7} ∣ f_{1} (x) - f_{2} (x) ∣ d x + \int_{7}^{8} ∣ f_{2} (x) - f_{3} (x) ∣ d x

= \int_{- 10}^{- \frac{35}{4}} 3 x - (70 - x^{2}) d x + \int_{- \frac{35}{4}}^{0} \frac{3}{4} x - 3 x d x + \int_{0}^{7} 3 x - \frac{3}{4} x d x + \int_{7}^{8} \frac{3}{4} x - (70 - x^{2}) d x

\int_{- 10}^{- \frac{35}{4}} 3 x - (70 - x^{2}) d x = \frac{2425}{192}

\int_{- \frac{35}{4}}^{0} \frac{3}{4} x - 3 x d x = \frac{11025}{128}

\int_{0}^{7} 3 x - \frac{3}{4} x d x = \frac{441}{8}

\int_{7}^{8} \frac{3}{4} x - (70 - x^{2}) d x = \frac{193}{24}

= \frac{2425}{192} + \frac{11025}{128} + \frac{441}{8} + \frac{193}{24}

Simplify

= \frac{20727}{128}

q^{^{''}} + 20 q^{^{'}} + 500 q = 12

x \to 1 lim (3 x^{2} - 2 x + 1)

\int cos^{2} (3 x) sin^{2} (3 x) d x

x \to 0 lim (x sin (\frac{5}{x}))

y^{^{'}} = \frac{( y + y ^{2} )}{x ^{2}}

What is area 3x, 3/4 x,70-x^2 ?
The answer to area 3x, 3/4 x,70-x^2 is 20727/128