What is the integral of (12)/(x^2+1) ?

The integral of (12)/(x^2+1) is 12arctan(x)+C

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integral of (12)/(x^2+1)

\int \frac{12}{x ^{2} + 1} d x

12 arctan (x) + C

Solution steps

\int \frac{12}{x ^{2} + 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 12 \cdot \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= 12 arctan (x)

Add a constant to the solution

= 12 arctan (x) + C

(1 - x)^{\frac{1}{5}}

\frac{d}{d x} (\frac{x}{1 + x})

\int (7 \frac{sin ( 2 x )}{sin ( x )}) d x

\int_{- 5}^{5} \frac{1}{2} (2 5^{2} - x^{4}) d x

\int \frac{x}{1 - x ^{2} + 1 - x ^{2}} d x

What is the integral of (12)/(x^2+1) ?
The integral of (12)/(x^2+1) is 12arctan(x)+C