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Popular >

y^'=18x^2e^{-y}

Solution

y^{^{'}} = 18 x^{2} e^{- y}

Solution

y = ln (6 x^{3} + c_{1})

Solution steps

y^{'} (x) = 18 x^{2} e^{- y}

Solve separable ODE:

y = ln (6 x^{3} + c_{1})

y = ln (6 x^{3} + c_{1})

Popular Examples

tangent of f(x)=x^2+3,\at x=2 tangent of

f (x) = x^{2} + 3, at x = 2

derivative of f(x)=ln(x^3+2x^2+2x)derivative of

f (x) = ln (x^{3} + 2 x^{2} + 2 x)

integral of 1/(x(x^2-1))

\int \frac{1}{x ( x ^{2} - 1 )} d x

integral of ((2x+1))/(x^2-2x+5)

\int \frac{( 2 x + 1 )}{x ^{2} - 2 x + 5} d x

limit as x approaches pi/4 of tan^2(x)

x \to \frac{π}{4} lim (tan^{2} (x))

Frequently Asked Questions (FAQ)

What is the solution for y^'=18x^2e^{-y} ?
The solution for y^'=18x^2e^{-y} is y=ln(6x^3+c_{1})