What is the limit as x approaches-1 of (x+2)/(x+1) ?

The limit as x approaches-1 of (x+2)/(x+1) is diverges

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limit as x approaches-1 of (x+2)/(x+1)

x \to - 1 lim (\frac{x + 2}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x + 2}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x + 2}{x + 1}) = \infty

x \to - 1 - lim (\frac{x + 2}{x + 1}) = - \infty

= diverges

\frac{6}{( s - 2 ) ^{6}}

f (x) = \frac{π}{x}

\int \frac{42 x ^{7} - 7 x}{7 x ^{5}} d x

\int \frac{1}{2 x ^{6}} d x

What is the limit as x approaches-1 of (x+2)/(x+1) ?
The limit as x approaches-1 of (x+2)/(x+1) is diverges