What is the tangent of x^2+x,\at x=-4 ?

The tangent of x^2+x,\at x=-4 is y=-7x-16

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tangent of x^2+x,\at x=-4

tangent of

x^{2} + x, at x = - 4

y = - 7 x - 16

Solution steps

Find the tangent point:

(- 4, 12)

Find the slope of

y = x^{2} + x : \frac{d y}{d x} = 2 x + 1

Compute the slope of

y = x^{2} + x

x = - 4 : m = - 7

Find the line with slope m=

- 7

and passing through

(- 4, 12) : y = - 7 x - 16

y = - 7 x - 16

\int x^{2} 6 x + 8 d x

\int arccos (d) x d x

x \to 3 π - lim (1 + csc (x))

\int_{- 10}^{10} \frac{10}{x ^{2} + 25} d x

y = \frac{x}{7 + x}

What is the tangent of x^2+x,\at x=-4 ?
The tangent of x^2+x,\at x=-4 is y=-7x-16