What is the derivative of 2x^2-16x+35 ?

The derivative of 2x^2-16x+35 is 4x-16

What is the first derivative of 2x^2-16x+35 ?

The first derivative of 2x^2-16x+35 is 4x-16

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\frac{d}{d x} (2 x^{2} - 16 x + 35)

4 x - 16

Solution steps

\frac{d}{d x} (2 x^{2} - 16 x + 35)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (16 x) + \frac{d}{d x} (35)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (16 x) = 16

\frac{d}{d x} (35) = 0

= 4 x - 16 + 0

Simplify

= 4 x - 16

\int e^{t a n (7 x)} sec^{2} (7 x) d x

y = 10 x

\frac{d}{d x} (\frac{3}{x ^{2} - 2 x})

\int \frac{4 x - 1}{3 - 4 x - x ^{2}} d x

\int (4 x^{3} + 1)^{6} 12 x^{2} d x

What is the derivative of 2x^2-16x+35 ?
The derivative of 2x^2-16x+35 is 4x-16
What is the first derivative of 2x^2-16x+35 ?
The first derivative of 2x^2-16x+35 is 4x-16