What is the derivative of (10/(sqrt(x^2-4x+1))) ?

The derivative of (10/(sqrt(x^2-4x+1))) is -(5(2x-4))/((x^2-4x+1)^{3/2)}

What is the first derivative of (10/(sqrt(x^2-4x+1))) ?

The first derivative of (10/(sqrt(x^2-4x+1))) is -(5(2x-4))/((x^2-4x+1)^{3/2)}

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\frac{d}{d x} (\frac{10}{x ^{2} - 4 x + 1})

- \frac{5 ( 2 x - 4 )}{( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{10}{x ^{2} - 4 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (\frac{1}{x ^{2} - 4 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 10 \frac{d}{d x} ((x^{2} - 4 x + 1)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} - 4 x + 1)

= - \frac{1}{2 ( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}} \frac{d}{d x} (x^{2} - 4 x + 1)

\frac{d}{d x} (x^{2} - 4 x + 1) = 2 x - 4

= 10 (- \frac{1}{2 ( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}} (2 x - 4))

Simplify

10 (- \frac{1}{2 ( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}} (2 x - 4)) : - \frac{5 ( 2 x - 4 )}{( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}}

= - \frac{5 ( 2 x - 4 )}{( x ^{2} - 4 x + 1 ) ^{\frac{3}{2}}}

\int (x + 7) (x - 3) d x

\int 4 x - 4 d x

\frac{d}{d x} (\frac{e ^{x^{2}}}{x ^{3}})

2 (x - 1)

\int e^{2 y - y^{2}} d y

What is the derivative of (10/(sqrt(x^2-4x+1))) ?
The derivative of (10/(sqrt(x^2-4x+1))) is -(5(2x-4))/((x^2-4x+1)^{3/2)}
What is the first derivative of (10/(sqrt(x^2-4x+1))) ?
The first derivative of (10/(sqrt(x^2-4x+1))) is -(5(2x-4))/((x^2-4x+1)^{3/2)}