What is the derivative of f(x)=2x+7 ?

The derivative of f(x)=2x+7 is 2

What is the first derivative of f(x)=2x+7 ?

The first derivative of f(x)=2x+7 is 2

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derivative of

f (x) = 2 x + 7

2

Solution steps

\frac{d}{d x} (2 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (7)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (7) = 0

= 2 + 0

Simplify

= 2

\int \frac{( x ^{2} - 1 )}{x ^{3} + x} d x

\frac{d}{d x} (- k e^{l (x - m)} + n e^{- p (x - m)} + q)

\frac{1}{( s - 2 ) ^{2} + 9}

\frac{d}{d j} (6 i + 10 j)

(x + y) d x - (x + y - 2) d y = 0

What is the derivative of f(x)=2x+7 ?
The derivative of f(x)=2x+7 is 2
What is the first derivative of f(x)=2x+7 ?
The first derivative of f(x)=2x+7 is 2