What is the solution for (dy)/(dt)= t/(ye^{y+t^2)} ?

The solution for (dy)/(dt)= t/(ye^{y+t^2)} is y=\W((-e^{-t^2}+c_{1})/(2e))+1

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(dy)/(dt)= t/(ye^{y+t^2)}

\frac{d y}{d t} = \frac{t}{y e ^{y + t^{2}}}

y = W (\frac{- e ^{- t^{2}} + c _{1}}{2 e}) + 1

Solution steps

\frac{d y}{d t} = \frac{t}{y e ^{y + t^{2}}}

Solve separable ODE:

y = W (\frac{- e ^{- t^{2}} + c _{1}}{2 e}) + 1

y = W (\frac{- e ^{- t^{2}} + c _{1}}{2 e}) + 1

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2 x y \frac{d y}{d x} = 1

What is the solution for (dy)/(dt)= t/(ye^{y+t^2)} ?
The solution for (dy)/(dt)= t/(ye^{y+t^2)} is y=\W((-e^{-t^2}+c_{1})/(2e))+1