What is the derivative of 2e^x+4/(\sqrt[3]{x)} ?

The derivative of 2e^x+4/(\sqrt[3]{x)} is 2e^x-4/(3x^{4/3)}

What is the first derivative of 2e^x+4/(\sqrt[3]{x)} ?

The first derivative of 2e^x+4/(\sqrt[3]{x)} is 2e^x-4/(3x^{4/3)}

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derivative of

2 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (2 e^{x}) = 2 e^{x}

= 2 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

\int_{0}^{4} x^{2} 16 - x^{2} d x

\frac{d y}{d x} - x y^{2} = 2 x y

n = 0 \sum \infty \frac{1}{2 ^{2 n}}

\int \frac{1}{6} e^{6 x} d x

x \to 3 lim (x^{2} - 3 x - 10)

What is the derivative of 2e^x+4/(\sqrt[3]{x)} ?
The derivative of 2e^x+4/(\sqrt[3]{x)} is 2e^x-4/(3x^{4/3)}
What is the first derivative of 2e^x+4/(\sqrt[3]{x)} ?
The first derivative of 2e^x+4/(\sqrt[3]{x)} is 2e^x-4/(3x^{4/3)}