What is the integral from 0 to pi/9 of 7-7cos(3x) ?

The integral from 0 to pi/9 of 7-7cos(3x) is (7pi)/9-7/(2sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/9 of 7-7cos(3x)

\int_{0}^{\frac{π}{9}} 7 - 7 cos (3 x) d x

\frac{7 π}{9} - \frac{7}{2 3}

Decimal Notation

0.42273 \dots

Solution steps

\int_{0}^{\frac{π}{9}} 7 - 7 cos (3 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{9}} 7 d x - \int_{0}^{\frac{π}{9}} 7 cos (3 x) d x

\int_{0}^{\frac{π}{9}} 7 d x = \frac{7 π}{9}

\int_{0}^{\frac{π}{9}} 7 cos (3 x) d x = \frac{7}{2 3}

= \frac{7 π}{9} - \frac{7}{2 3}

x \to 1 lim (- \frac{x}{x ^{2} - x})

f (x) = (csc (3 x - 1))^{\frac{2}{3}}

\int \frac{15 y ^{2} - 2}{y ^{2}} d y

f (x) = 6 tan (x)

\int x^{2} + 2 x d x

What is the integral from 0 to pi/9 of 7-7cos(3x) ?
The integral from 0 to pi/9 of 7-7cos(3x) is (7pi)/9-7/(2sqrt(3))