What is (\partial)/(\partial x)(e^{4x}cos(7y)) ?

The answer to (\partial)/(\partial x)(e^{4x}cos(7y)) is cos(7y)e^{4x}*4

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(\partial)/(\partial x)(e^{4x}cos(7y))

\frac{\partial}{\partial x} (e^{4 x} cos (7 y))

cos (7 y) e^{4 x} \cdot 4

Solution steps

\frac{\partial}{\partial x} (e^{4 x} cos (7 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (7 y) \frac{\partial}{\partial x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{\partial}{\partial x} (4 x)

= e^{4 x} \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= cos (7 y) e^{4 x} \cdot 4

\frac{d}{d y} (y^{- 1})

\frac{d}{d x} (x^{2} e^{x} - 3)

x \to 0 lim (x \cdot arctan (\frac{1}{x}))

\int (2 x^{3} + 3 x + 1)^{4} (6 x^{2} + 3) d x

\int \frac{1}{x ( 1 + x ^{2} )} d x

What is (\partial)/(\partial x)(e^{4x}cos(7y)) ?
The answer to (\partial)/(\partial x)(e^{4x}cos(7y)) is cos(7y)e^{4x}*4