What is the integral of (2-sqrt(x))^2 ?

The integral of (2-sqrt(x))^2 is 4x-8/3 x^{3/2}+(x^2)/2+C

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integral of (2-sqrt(x))^2

\int (2 - x)^{2} d x

4 x - \frac{8}{3} x^{\frac{3}{2}} + \frac{x ^{2}}{2} + C

Solution steps

\int (2 - x)^{2} d x

Expand

(2 - x)^{2} : 4 - 4 x + x

= \int 4 - 4 x + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 d x - \int 4 x d x + \int x d x

\int 4 d x = 4 x

\int 4 x d x = \frac{8}{3} x^{\frac{3}{2}}

\int x d x = \frac{x ^{2}}{2}

= 4 x - \frac{8}{3} x^{\frac{3}{2}} + \frac{x ^{2}}{2}

Add a constant to the solution

= 4 x - \frac{8}{3} x^{\frac{3}{2}} + \frac{x ^{2}}{2} + C

3 y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = - 7, y^{^{'}} (0) = - 8

\int (e^{x} + x) d x

y = 4 x^{2} + 5 x + 1, (0, 1)

\frac{d}{d x} (lo g_{10} (lo g_{10} (x)))

\int sin^{2} (θ) cos (4 θ) d θ

What is the integral of (2-sqrt(x))^2 ?
The integral of (2-sqrt(x))^2 is 4x-8/3 x^{3/2}+(x^2)/2+C