What is the derivative of y=sqrt(16-x^2) ?

The derivative of y=sqrt(16-x^2) is -x/(sqrt(16-x^2))

What is the first derivative of y=sqrt(16-x^2) ?

The first derivative of y=sqrt(16-x^2) is -x/(sqrt(16-x^2))

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derivative of

y = 16 - x^{2}

- \frac{x}{16 - x ^{2}}

Solution steps

\frac{d}{d x} (16 - x^{2})

Apply the chain rule:

\frac{1}{2 16 - x ^{2}} \frac{d}{d x} (16 - x^{2})

= \frac{1}{2 16 - x ^{2}} \frac{d}{d x} (16 - x^{2})

\frac{d}{d x} (16 - x^{2}) = - 2 x

= \frac{1}{2 16 - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 16 - x ^{2}} (- 2 x) : - \frac{x}{16 - x ^{2}}

= - \frac{x}{16 - x ^{2}}

\frac{\partial}{\partial x} ((a - x)^{2} + b (y - x^{2})^{2})

\int 6 x^{2} y d y

\frac{\partial}{\partial L} (b L^{3} K (b) (b)^{2})

y = \frac{( x ^{2} - 1 )}{( x ^{2} + x + 1 )}

What is the derivative of y=sqrt(16-x^2) ?
The derivative of y=sqrt(16-x^2) is -x/(sqrt(16-x^2))
What is the first derivative of y=sqrt(16-x^2) ?
The first derivative of y=sqrt(16-x^2) is -x/(sqrt(16-x^2))