What is the solution for (y^2+yx)dx+(x^2)dy=0 ?

The solution for (y^2+yx)dx+(x^2)dy=0 is y=(2x)/(-1+2c_{1)x^2}

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(y^2+yx)dx+(x^2)dy=0

(y^{2} + y x) d x + (x^{2}) d y = 0

y = \frac{2 x}{- 1 + 2 c _{1} x ^{2}}

Solution steps

(y^{2} + y x) d x + (x^{2}) d y = 0

Solve Bernoulli ODE:

y = \frac{2 x}{- 1 + 2 c _{1} x ^{2}}

y = \frac{2 x}{- 1 + 2 c _{1} x ^{2}}

y = (x - 2)^{4}

\frac{d}{d x} (cos ((2 x^{2} + 1)^{7}))

x \to \frac{π}{4} lim (cot (x))

\int_{0}^{\frac{π}{2}} tan (x) d x

What is the solution for (y^2+yx)dx+(x^2)dy=0 ?
The solution for (y^2+yx)dx+(x^2)dy=0 is y=(2x)/(-1+2c_{1)x^2}