What is the tangent of f(x)=(8-9x)(8+9x),\at x=9 ?

The tangent of f(x)=(8-9x)(8+9x),\at x=9 is y=-1458x+6625

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tangent of f(x)=(8-9x)(8+9x),\at x=9

tangent of

f (x) = (8 - 9 x) (8 + 9 x), at x = 9

y = - 1458 x + 6625

Solution steps

Find the tangent point:

(9, - 6497)

Find the slope of

f (x) = (8 - 9 x) (8 + 9 x) : \frac{df ( x )}{d x} = - 162 x

Compute the slope of

f (x) = (8 - 9 x) (8 + 9 x)

x = 9 : m = - 1458

Find the line with slope m=

- 1458

and passing through

(9, - 6497) : y = - 1458 x + 6625

y = - 1458 x + 6625

x \to \infty lim (x^{2} + 2)

\int 5 - 2 x + x^{2} d x

\frac{\partial}{\partial y} (\frac{4 x - y}{4 x + y})

(6 + x) y^{^{'}} = 9 y

\int \frac{x + 1}{x ^{2} + 2 x + 4} d x

What is the tangent of f(x)=(8-9x)(8+9x),\at x=9 ?
The tangent of f(x)=(8-9x)(8+9x),\at x=9 is y=-1458x+6625