What is (\partial)/(\partial x)(25-5x^2-y^2) ?

The answer to (\partial)/(\partial x)(25-5x^2-y^2) is -10x

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(\partial)/(\partial x)(25-5x^2-y^2)

\frac{\partial}{\partial x} (25 - 5 x^{2} - y^{2})

- 10 x

Solution steps

\frac{\partial}{\partial x} (25 - 5 x^{2} - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (25) - \frac{\partial}{\partial x} (5 x^{2}) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (25) = 0

\frac{\partial}{\partial x} (5 x^{2}) = 10 x

\frac{\partial}{\partial x} (y^{2}) = 0

= 0 - 10 x - 0

Simplify

= - 10 x

x \to \infty lim (2 x + 5)

\int_{0}^{π} 3 sin^{2} (t co) s^{4} t d t

f (x) = \frac{3 x ^{2} e ^{x} - 4}{x ^{2}}

x \to 1 - lim (2 x^{4} - 9 x^{3} + 7)

(\frac{3 y}{x} - 8) d x + 3 d y = 0

What is (\partial)/(\partial x)(25-5x^2-y^2) ?
The answer to (\partial)/(\partial x)(25-5x^2-y^2) is -10x