What is the derivative of f(x)=(-4x^2+16)^2 ?

The derivative of f(x)=(-4x^2+16)^2 is -16x(-4x^2+16)

What is the first derivative of f(x)=(-4x^2+16)^2 ?

The first derivative of f(x)=(-4x^2+16)^2 is -16x(-4x^2+16)

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derivative of

f (x) = (- 4 x^{2} + 16)^{2}

- 16 x (- 4 x^{2} + 16)

Solution steps

\frac{d}{d x} ((- 4 x^{2} + 16)^{2})

Apply the chain rule:

2 (- 4 x^{2} + 16) \frac{d}{d x} (- 4 x^{2} + 16)

= 2 (- 4 x^{2} + 16) \frac{d}{d x} (- 4 x^{2} + 16)

\frac{d}{d x} (- 4 x^{2} + 16) = - 8 x

= 2 (- 4 x^{2} + 16) (- 8 x)

Simplify

= - 16 x (- 4 x^{2} + 16)

\int_{0}^{\frac{π}{4}} ln (sec (x)) d x

\int \frac{8 m ^{2}}{( m ^{3} + 2 ) ^{3}} d m

x \to 0 + lim (x^{\frac{5}{x}})

x \to 0 lim (\frac{3}{10 - e ^{x}})

\int 2 e^{2}

What is the derivative of f(x)=(-4x^2+16)^2 ?
The derivative of f(x)=(-4x^2+16)^2 is -16x(-4x^2+16)
What is the first derivative of f(x)=(-4x^2+16)^2 ?
The first derivative of f(x)=(-4x^2+16)^2 is -16x(-4x^2+16)