What is the derivative of f(x)=x^2+4 ?

The derivative of f(x)=x^2+4 is 2x

What is the first derivative of f(x)=x^2+4 ?

The first derivative of f(x)=x^2+4 is 2x

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derivative of

f (x) = x^{2} + 4

2 x

Solution steps

\frac{d}{d x} (x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4) = 0

= 2 x + 0

Simplify

= 2 x

(\frac{y}{x} + 3 x) d x + (ln (x) - 2) d y = 0

\int \frac{x ^{2} - 2 x}{x ^{3} - 3 x ^{2}} d x

- 3 t (6 t^{3} - 1)^{8}

\int_{0}^{π} x sin (x) d x

\frac{d}{d x} ((- 2 x^{2} - 2 x + 3)^{5})

What is the derivative of f(x)=x^2+4 ?
The derivative of f(x)=x^2+4 is 2x
What is the first derivative of f(x)=x^2+4 ?
The first derivative of f(x)=x^2+4 is 2x