What is the integral of ((2x-5)/7) ?

The integral of ((2x-5)/7) is 1/7 (x^2-5x)+C

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integral of ((2x-5)/7)

\int (\frac{2 x - 5}{7}) d x

\frac{1}{7} (x^{2} - 5 x) + C

Solution steps

\int \frac{2 x - 5}{7} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int 2 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{7} (\int 2 x d x - \int 5 d x)

\int 2 x d x = x^{2}

\int 5 d x = 5 x

= \frac{1}{7} (x^{2} - 5 x)

Add a constant to the solution

= \frac{1}{7} (x^{2} - 5 x) + C

\int (sec^{2} (x) - 9) d x

\int_{0}^{2} \frac{3 x ^{2} - 1}{x ^{2}} d x

y = 2 x^{3} - x^{2} + 7

\frac{\partial}{\partial x} (\frac{t}{a ^{2} t ^{2} - x ^{2}})

\frac{e ^{x} + 1}{e ^{x} - 1}

What is the integral of ((2x-5)/7) ?
The integral of ((2x-5)/7) is 1/7 (x^2-5x)+C