What is the derivative of acos(x-bsin(x)) ?

The derivative of acos(x-bsin(x)) is -asin(x)-bcos(x)

What is the first derivative of acos(x-bsin(x)) ?

The first derivative of acos(x-bsin(x)) is -asin(x)-bcos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (a cos (x) - b sin (x))

- a sin (x) - b cos (x)

Solution steps

\frac{d}{d x} (a cos (x) - b sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (x)) - \frac{d}{d x} (b sin (x))

\frac{d}{d x} (a cos (x)) = - a sin (x)

\frac{d}{d x} (b sin (x)) = b cos (x)

= - a sin (x) - b cos (x)

\frac{d}{d x} (\frac{24}{( x - 1 ) ^{5}})

(- 4, - 9), (7, 7)

\frac{\partial}{\partial x} (x y cos (6 yz))

\frac{\partial}{\partial x} (- x^{3})

\frac{\partial}{\partial x} (- \frac{1}{2} x - 3 y + 1)

What is the derivative of acos(x-bsin(x)) ?
The derivative of acos(x-bsin(x)) is -asin(x)-bcos(x)
What is the first derivative of acos(x-bsin(x)) ?
The first derivative of acos(x-bsin(x)) is -asin(x)-bcos(x)