What is the derivative of f(x)= 1/(x^4) ?

The derivative of f(x)= 1/(x^4) is -4/(x^5)

What is the first derivative of f(x)= 1/(x^4) ?

The first derivative of f(x)= 1/(x^4) is -4/(x^5)

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derivative of

f (x) = \frac{1}{x ^{4}}

- \frac{4}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 4 x^{- 4 - 1}

Simplify

- 4 x^{- 4 - 1} : - \frac{4}{x ^{5}}

= - \frac{4}{x ^{5}}

y d x = x d y

\int \frac{sin ( θ ) cos ( θ )}{1 + sin ^{2} ( θ )} d θ

\frac{\partial}{\partial x} (x^{3} + y^{3})

\frac{\partial}{\partial x} (ln (x^{2} + 3 y))

x \to \infty lim (1 - x^{2})

What is the derivative of f(x)= 1/(x^4) ?
The derivative of f(x)= 1/(x^4) is -4/(x^5)
What is the first derivative of f(x)= 1/(x^4) ?
The first derivative of f(x)= 1/(x^4) is -4/(x^5)