What is the d/(dy)(sqrt(9-y^2)) ?

The d/(dy)(sqrt(9-y^2)) is -y/(sqrt(9-y^2))

What is the first d/(dy)(sqrt(9-y^2)) ?

The first d/(dy)(sqrt(9-y^2)) is -y/(sqrt(9-y^2))

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\frac{d}{d y} (9 - y^{2})

- \frac{y}{9 - y ^{2}}

Solution steps

\frac{d}{d y} (9 - y^{2})

Apply the chain rule:

\frac{1}{2 9 - y ^{2}} \frac{d}{d y} (9 - y^{2})

= \frac{1}{2 9 - y ^{2}} \frac{d}{d y} (9 - y^{2})

\frac{d}{d y} (9 - y^{2}) = - 2 y

= \frac{1}{2 9 - y ^{2}} (- 2 y)

Simplify

\frac{1}{2 9 - y ^{2}} (- 2 y) : - \frac{y}{9 - y ^{2}}

= - \frac{y}{9 - y ^{2}}

\frac{d}{d x} (2^{x} + 2 cos (\frac{2 x}{2}))

\int 7 x^{3} x^{4} + 6 d x

(- 9, - 3), (7, - 7)

\frac{d}{d x} (π e^{(\frac{2}{π x})})

\frac{40}{0.01 x ^{2} + 1}

What is the d/(dy)(sqrt(9-y^2)) ?
The d/(dy)(sqrt(9-y^2)) is -y/(sqrt(9-y^2))
What is the first d/(dy)(sqrt(9-y^2)) ?
The first d/(dy)(sqrt(9-y^2)) is -y/(sqrt(9-y^2))