What is (\partial)/(\partial z)(2z^{10}) ?

The answer to (\partial)/(\partial z)(2z^{10}) is 20z^9

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(\partial)/(\partial z)(2z^{10})

\frac{\partial}{\partial z} (2 z^{10})

20 z^{9}

Solution steps

\frac{\partial}{\partial z} (2 z^{10})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial z} (z^{10})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 10 z^{10 - 1}

Simplify

= 20 z^{9}

\int \frac{13}{x} d x

\frac{\partial}{\partial x} (- 2 x y z^{- 1})

x \to - 5 lim (\frac{x}{x + 4})

n = 0 \sum \infty n \cdot sin (nπ)

x \to 6 lim (\frac{∣ x - 6 ∣}{x - 6})

What is (\partial)/(\partial z)(2z^{10}) ?
The answer to (\partial)/(\partial z)(2z^{10}) is 20z^9