What is the derivative of y^2-cos(x) ?

The derivative of y^2-cos(x) is 2y(dy)/(dx)+sin(x)

What is the first derivative of y^2-cos(x) ?

The first derivative of y^2-cos(x) is 2y(dy)/(dx)+sin(x)

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\frac{d}{d x} (y^{2} - cos (x))

2 y \frac{d y}{d x} + sin (x)

Solution steps

\frac{d}{d x} (y^{2} - cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (y^{2}) - \frac{d}{d x} (cos (x))

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 y \frac{d y}{d x} - (- sin (x))

Simplify

= 2 y \frac{d y}{d x} + sin (x)

\frac{( s + 5 )}{s ( s + 4 ) ^{2}}

\int \frac{cos ( x )}{5 + sin ^{2} ( x )} d x

\frac{d y}{d x} = 6 e^{x - y}

\frac{d}{d x} (x^{3} + x)

n = 1 \sum \infty \frac{1}{n ^{2} + 5}

What is the derivative of y^2-cos(x) ?
The derivative of y^2-cos(x) is 2y(dy)/(dx)+sin(x)
What is the first derivative of y^2-cos(x) ?
The first derivative of y^2-cos(x) is 2y(dy)/(dx)+sin(x)