What is the solution for x derivative of ln(y)=1 ?

The solution for x derivative of ln(y)=1 is y=c_{1}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x derivative of ln(y)=1

x \frac{d}{d x} (ln (y)) = 1

y = c_{1} x

Solution steps

x \frac{d}{d x} (ln (y)) = 1

Isolate

(ln (y))^{'} : (ln (y))^{'} = \frac{1}{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

ln (y) = \int \frac{1}{x} d x

\int \frac{1}{x} d x = ln (x) + c_{1}

ln (y) = ln (x) + c_{1}

Isolate

y : y = e^{c_{1}} x

y = e^{c_{1}} x

Simplify

y = c_{1} x

x \to 2 + lim (\frac{1}{x + 2})

\frac{d}{d x} (33 (10 x - x + 10.45))

x \to 3 + lim (\frac{x - 4}{3 - x})

\frac{d}{d t} (5 t)

lo g_{10} (x + 1)

What is the solution for x derivative of ln(y)=1 ?
The solution for x derivative of ln(y)=1 is y=c_{1}x