What is the first derivative of 2ay ?

The first derivative of 2ay is 2a

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derivative of 2ay

derivative of

2 a y

2 a

Solution steps

\frac{d}{d y} (2 a y)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 a \frac{d y}{d y}

Apply the common derivative:

\frac{d y}{d y} = 1

= 2 a \cdot 1

Simplify

= 2 a

f (x) = e^{y^{2}} + 2 x^{3}

\frac{\partial}{\partial y} (2 cos (x + 2 y))

\int \frac{x ^{2} - 4}{x ( x ^{2} + 4 )} d x

\int cos^{5} (θ) sin (θ) d θ

y = x, y = 2 x 49 - x^{2}