What is the integral from 0 to 1 of ln(5x) ?

The integral from 0 to 1 of ln(5x) is ln(5)-1

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integral from 0 to 1 of ln(5x)

\int_{0}^{1} ln (5 x) d x

ln (5) - 1

Decimal Notation

0.60943 \dots

Solution steps

\int_{0}^{1} ln (5 x) d x

Apply Integration By Parts

: [x ln (5 x) - \int 1 d x]_{0}^{1}

= [x ln (5 x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= [x ln (5 x) - x]_{0}^{1}

Compute the boundaries:

ln (5) - 1

= ln (5) - 1

x \to 0 lim (9 x^{2} + 6 x)

\frac{d}{d x} (\frac{( 2 x ^{2} + 8 x + 4 )}{x})

\int x^{3} (x^{4} - 3)^{4} d x

\int \frac{( ln ( x ) ) ^{26}}{x} d x

\int_{0}^{\frac{1}{2}} x 1 - 4 x^{2} d x

What is the integral from 0 to 1 of ln(5x) ?
The integral from 0 to 1 of ln(5x) is ln(5)-1