What is the solution for y^'= x/(200)-y/(100) ?

The solution for y^'= x/(200)-y/(100) is y=(x-100)/2+(c_{1})/(e^{x/(100))}

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y^'= x/(200)-y/(100)

y^{^{'}} = \frac{x}{200} - \frac{y}{100}

y = \frac{x - 100}{2} + \frac{c _{1}}{e ^{\frac{x}{100}}}

Solution steps

y^{'} (x) = \frac{x}{200} - \frac{y}{100}

Solve linear ODE:

y = \frac{x - 100}{2} + \frac{c _{1}}{e ^{\frac{x}{100}}}

y = \frac{x - 100}{2} + \frac{c _{1}}{e ^{\frac{x}{100}}}

\frac{d}{d x} (\frac{1}{3} x^{3} - \frac{5}{2} x^{2} + 6 x + 1)

\int - \frac{1}{x} \cdot \frac{1}{x} d x

f (x) = x - 1

\int θ sec (θ) tan (θ) d θ

(\frac{f ( x ) + x - 6}{4 - 2 x})^{'}

What is the solution for y^'= x/(200)-y/(100) ?
The solution for y^'= x/(200)-y/(100) is y=(x-100)/2+(c_{1})/(e^{x/(100))}