What is the derivative of 16ln(x^2-x^2) ?

The derivative of 16ln(x^2-x^2) is (32)/x-2x

What is the first derivative of 16ln(x^2-x^2) ?

The first derivative of 16ln(x^2-x^2) is (32)/x-2x

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\frac{d}{d x} (16 ln (x^{2}) - x^{2})

\frac{32}{x} - 2 x

Solution steps

\frac{d}{d x} (16 ln (x^{2}) - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (16 ln (x^{2})) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (16 ln (x^{2})) = \frac{32}{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{32}{x} - 2 x

\int \frac{x ^{3}}{x ^{2} + 64} d x

2^{x}

\frac{d}{d x} ((x + ln (x^{2}))^{s i n (x) + 2 c o s (x)})

\frac{\partial}{\partial x} (6 x^{2} y + 1)

x \to 3 lim (\frac{1}{3 x ^{2} - 27})

What is the derivative of 16ln(x^2-x^2) ?
The derivative of 16ln(x^2-x^2) is (32)/x-2x
What is the first derivative of 16ln(x^2-x^2) ?
The first derivative of 16ln(x^2-x^2) is (32)/x-2x