What is the integral of (sin(x))/(1+2cos(x)) ?

The integral of (sin(x))/(1+2cos(x)) is -1/2 ln|1+2cos(x)|+C

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integral of (sin(x))/(1+2cos(x))

\int \frac{sin ( x )}{1 + 2 cos ( x )} d x

- \frac{1}{2} ln ∣ 1 + 2 cos (x) ∣ + C

Solution steps

\int \frac{sin ( x )}{1 + 2 cos ( x )} d x

Apply u-substitution

: \int - \frac{1}{2 u} d u

= \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{2} ln ∣ u ∣

Substitute back

u = 1 + 2 cos (x)

= - \frac{1}{2} ln ∣ 1 + 2 cos (x) ∣

Add a constant to the solution

= - \frac{1}{2} ln ∣ 1 + 2 cos (x) ∣ + C

\frac{d y}{d x} y = x^{- 8}

\int \frac{1}{( 1 - 6 t ) ^{4}} d t

cos^{2} (3 t)

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (2 t)

What is the integral of (sin(x))/(1+2cos(x)) ?
The integral of (sin(x))/(1+2cos(x)) is -1/2 ln|1+2cos(x)|+C