What is the derivative of (hx/2+(kd)/x) ?

The derivative of (hx/2+(kd)/x) is h/2-(kd)/(x^2)

What is the first derivative of (hx/2+(kd)/x) ?

The first derivative of (hx/2+(kd)/x) is h/2-(kd)/(x^2)

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\frac{d}{d x} (\frac{h x}{2} + \frac{k d}{x})

\frac{h}{2} - \frac{k d}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{h x}{2} + \frac{k d}{x})

Treat

h, k, d

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{h x}{2}) + \frac{d}{d x} (\frac{k d}{x})

\frac{d}{d x} (\frac{h x}{2}) = \frac{h}{2}

\frac{d}{d x} (\frac{k d}{x}) = - \frac{k d}{x ^{2}}

= \frac{h}{2} - \frac{k d}{x ^{2}}

\frac{\partial}{\partial x} (x \cdot e^{\frac{y}{x}})

f^{^{'}} (x) = \frac{4}{1 - 2 x ^{2}}

sin (t^{2}) ln (t^{3})

\int (e^{\frac{x}{a}} - e^{- \frac{x}{a}})^{2} d x

\int 4 e^{x} d x

What is the derivative of (hx/2+(kd)/x) ?
The derivative of (hx/2+(kd)/x) is h/2-(kd)/(x^2)
What is the first derivative of (hx/2+(kd)/x) ?
The first derivative of (hx/2+(kd)/x) is h/2-(kd)/(x^2)