What is the derivative of-3x^2+6x ?

The derivative of-3x^2+6x is -6x+6

What is the first derivative of-3x^2+6x ?

The first derivative of-3x^2+6x is -6x+6

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\frac{d}{d x} (- 3 x^{2} + 6 x)

- 6 x + 6

Solution steps

\frac{d}{d x} (- 3 x^{2} + 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

= - 6 x + 6

x e^{3 x} (2 + 3 x)

f (x) = x^{11} arccos (x)

\frac{\partial}{\partial y} (sin (y) + y sin (x))

x \to 5 - lim (3)

y^{^{''}} = x^{2} - 1

What is the derivative of-3x^2+6x ?
The derivative of-3x^2+6x is -6x+6
What is the first derivative of-3x^2+6x ?
The first derivative of-3x^2+6x is -6x+6