What is the solution for x/y (dy)/(dx)+ln(y)=x+1 ?

The solution for x/y (dy)/(dx)+ln(y)=x+1 is y=e^{(c_{1})/x+x/2+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x/y (dy)/(dx)+ln(y)=x+1

\frac{x}{y} \frac{d y}{d x} + ln (y) = x + 1

y = e^{\frac{c _{1}}{x} + \frac{x}{2} + 1}

Solution steps

\frac{x}{y} \frac{d y}{d x} + ln (y) = x + 1

Solve exact ODE:

y = e^{\frac{c _{1}}{x} + \frac{x}{2} + 1}

y = e^{\frac{c _{1}}{x} + \frac{x}{2} + 1}

\int \frac{3}{4} x^{4} d x

x \to 2 + lim (\frac{2 x + 1}{x - 2})

cos (x^{5})

n = 0 \sum \infty (\frac{π}{e})^{n}

\frac{e ^{- 2 x}}{2 x ^{2} + 1}

What is the solution for x/y (dy)/(dx)+ln(y)=x+1 ?
The solution for x/y (dy)/(dx)+ln(y)=x+1 is y=e^{(c_{1})/x+x/2+1}