en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-2x^2+8x

Solution

\int - 2 x^{2} + 8 x d x

Solution

- \frac{2 x ^{3}}{3} + 4 x^{2} + C

Solution steps

\int - 2 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 x^{2} d x + \int 8 x d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 8 x d x = 4 x^{2}

= - \frac{2 x ^{3}}{3} + 4 x^{2}

Add a constant to the solution

= - \frac{2 x ^{3}}{3} + 4 x^{2} + C

Popular Examples

y^{''}-3y^'+y=0

y^{^{''}} - 3 y^{^{'}} + y = 0

tangent of y=3x^3-3x tangent of

y = 3 x^{3} - 3 x

\frac{d y}{d x} = 5 e^{x}

derivative of ln(1+cos(x))

\frac{d}{d x} (ln (1 + cos (x)))

integral from 0 to 1 of xarcsin(x^2)

\int_{0}^{1} x arcsin (x^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral of-2x^2+8x ?
The integral of-2x^2+8x is -(2x^3)/3+4x^2+C