What is the solution for (dy)/(dx)=xy+4x+5y+20 ?

The solution for (dy)/(dx)=xy+4x+5y+20 is y=e^{(x^2)/2+5x+c_{1}}-4

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(dy)/(dx)=xy+4x+5y+20

\frac{d y}{d x} = x y + 4 x + 5 y + 20

y = e^{\frac{x ^{2}}{2} + 5 x + c_{1}} - 4

Solution steps

\frac{d y}{d x} = x y + 4 x + 5 y + 20

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + 5 x + c_{1}} - 4

y = e^{\frac{x ^{2}}{2} + 5 x + c_{1}} - 4

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\int_{0}^{2} \frac{3}{16 - x ^{2}} d x

\frac{d}{d x} ((cos (x))^{\frac{π}{5}})

\int_{- 2}^{3} \frac{45}{x ^{4}} d x

\frac{d y}{d x} = \frac{x + y}{x + y + 2}

What is the solution for (dy)/(dx)=xy+4x+5y+20 ?
The solution for (dy)/(dx)=xy+4x+5y+20 is y=e^{(x^2)/2+5x+c_{1}}-4