What is the sum from n=0 to infinity of ((n))/(n+1) ?

The sum from n=0 to infinity of ((n))/(n+1) is diverges

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sum from n=0 to infinity of ((n))/(n+1)

n = 0 \sum \infty \frac{( n )}{n + 1}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{n + 1}

Apply Series Divergence Test:

diverges

= diverges

\frac{y}{x ^{2}} \frac{d y}{d x} + e^{2 x^{3} + y^{2}} = 0

x \to \infty lim (\frac{4}{x} - 12)

\frac{\partial}{\partial y} (3 x + 2 y sin (x))

x \to 20 lim (sin (70 - x))

f (x) = (2 x^{4} - 1) (5 x^{3} + 6 x)

What is the sum from n=0 to infinity of ((n))/(n+1) ?
The sum from n=0 to infinity of ((n))/(n+1) is diverges