What is the integral from-infinity to 0 of 7^x ?

The integral from-infinity to 0 of 7^x is 1/(ln(7))

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integral from-infinity to 0 of 7^x

\int_{- \infty}^{0} 7^{x} d x

\frac{1}{ln ( 7 )}

Decimal Notation

0.51389 \dots

Solution steps

\int_{- \infty}^{0} 7^{x} d x

Compute the indefinite integral:

\int 7^{x} d x = \frac{7 ^{x}}{ln ( 7 )} + C

Compute the boundaries:

\int_{- \infty}^{0} 7^{x} d x = \frac{1}{ln ( 7 )} - 0

= \frac{1}{ln ( 7 )} - 0

Simplify

= \frac{1}{ln ( 7 )}

e^{2 t} t^{3}

\int \frac{2}{x ^{3} x ^{2} - 1} d x

\int (2 x - y) d x

\frac{\partial}{\partial y} (y^{2} x)

What is the integral from-infinity to 0 of 7^x ?
The integral from-infinity to 0 of 7^x is 1/(ln(7))