What is the derivative of 3x^2+1/(x^3) ?

The derivative of 3x^2+1/(x^3) is 6x-3/(x^4)

What is the first derivative of 3x^2+1/(x^3) ?

The first derivative of 3x^2+1/(x^3) is 6x-3/(x^4)

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\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{3}})

6 x - \frac{3}{x ^{4}}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{1}{x ^{3}})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{x ^{3}}) = - \frac{3}{x ^{4}}

= 6 x - \frac{3}{x ^{4}}

x \to 0 - lim (sin (\frac{1}{x}))

\frac{d}{d x} (e^{x} (3 x^{2} + 5 x - 1))

\int 1 - 2 cos (2 x) d x

\int \frac{1}{2 x ^{2} x ^{2} - 9} d x

f (x) = (5 x - 5)^{\frac{1}{4}}, at x = 2

What is the derivative of 3x^2+1/(x^3) ?
The derivative of 3x^2+1/(x^3) is 6x-3/(x^4)
What is the first derivative of 3x^2+1/(x^3) ?
The first derivative of 3x^2+1/(x^3) is 6x-3/(x^4)