What is the limit as x approaches 1 of x-1/(ln|x|) ?

The limit as x approaches 1 of x-1/(ln|x|) is diverges

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limit as x approaches 1 of x-1/(ln|x|)

x \to 1 lim (x - \frac{1}{ln ∣ x ∣})

diverges

Solution steps

x \to 1 lim (x - \frac{1}{ln ∣ x ∣})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (x - \frac{1}{ln ∣ x ∣}) = - \infty

x \to 1 - lim (x - \frac{1}{ln ∣ x ∣}) = \infty

= diverges

6 x^{2} y^{^{'}} = y^{^{'}} + 8 x e^{- y}

\int \frac{4 x ^{2} + 4 x - 4}{x ^{3} + x ^{2} - x - 1} d x

\frac{\partial}{\partial y} (2 x z^{3} e^{y^{2}})

x, at x = 1

What is the limit as x approaches 1 of x-1/(ln|x|) ?
The limit as x approaches 1 of x-1/(ln|x|) is diverges