What is the derivative of y=4x^2-2x+(-9) ?

The derivative of y=4x^2-2x+(-9) is 8x-2

What is the first derivative of y=4x^2-2x+(-9) ?

The first derivative of y=4x^2-2x+(-9) is 8x-2

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derivative of

y = 4 x^{2} - 2 x + (- 9)

8 x - 2

Solution steps

\frac{d}{d x} (4 x^{2} - 2 x - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (9)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (9) = 0

= 8 x - 2 - 0

Simplify

= 8 x - 2

\frac{d}{d u} (uv)

\int 7 x^{\frac{3}{4}} d x

\frac{d y}{d x} = 2 sec^{2} (x) (y + 3)

\frac{d}{d x} (\frac{x ^{2} + 2 x - 2}{x ^{2} - 2 x + 2})

\int \frac{1}{x ^{2} 324 - x ^{2}} d x

What is the derivative of y=4x^2-2x+(-9) ?
The derivative of y=4x^2-2x+(-9) is 8x-2
What is the first derivative of y=4x^2-2x+(-9) ?
The first derivative of y=4x^2-2x+(-9) is 8x-2