What is the limit as x approaches 2+of ln|x-2| ?

The limit as x approaches 2+of ln|x-2| is -infinity

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limit as x approaches 2+of ln|x-2|

x \to 2 + lim (ln ∣ x - 2 ∣)

- \infty

Solution steps

x \to 2 + lim (ln ∣ x - 2 ∣)

x - 2

is positive when

x \to 2 +

. Therefore

∣ x - 2 ∣ = x - 2

= x \to 2 + lim (ln (x - 2))

Apply the Limit Chain Rule:

- \infty

= - \infty

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\int \frac{15}{4 - 5 x} d x

What is the limit as x approaches 2+of ln|x-2| ?
The limit as x approaches 2+of ln|x-2| is -infinity