What is (\partial)/(\partial x)(A+B(x^2+y^2)) ?

The answer to (\partial)/(\partial x)(A+B(x^2+y^2)) is 2Bx

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(\partial)/(\partial x)(A+B(x^2+y^2))

\frac{\partial}{\partial x} (A + B (x^{2} + y^{2}))

2 B x

Solution steps

\frac{\partial}{\partial x} (A + B (x^{2} + y^{2}))

Treat

A, B, y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (A) + \frac{\partial}{\partial x} (B (x^{2} + y^{2}))

\frac{\partial}{\partial x} (A) = 0

\frac{\partial}{\partial x} (B (x^{2} + y^{2})) = 2 B x

= 0 + 2 B x

Simplify

= 2 B x

x \to 1 lim (- 2 x + 5)

\frac{d}{d x} (2 (x - 1)^{\frac{3}{2}})

(x^{5} + y^{5}) d x + 5 x y^{4} d y = 0

\int \frac{x sec ( x )}{3 x} d x

x \to 0 lim (3 x^{3} - 2 x^{2} + 5)

What is (\partial)/(\partial x)(A+B(x^2+y^2)) ?
The answer to (\partial)/(\partial x)(A+B(x^2+y^2)) is 2Bx