What is integral from 0 to 6 of f(x) ?

The answer to integral from 0 to 6 of f(x) is f*18

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integral from 0 to 6 of f(x)

\int_{0}^{6} f (x) d x

f \cdot 18

Solution steps

\int_{0}^{6} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{6} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{6}

= f [\frac{x ^{2}}{2}]_{0}^{6}

Compute the boundaries:

18

= f \cdot 18

\frac{d}{d x} (x^{2} + 2 x + 8)

\frac{\partial}{\partial x} (x^{2} - 2 x y + 3 y^{2} + 2 x - 2 y)

f (x) = (2) (e^{3 x})

\frac{d}{d x} (- ∣ x ∣)

(3 x + 1)^{2}

What is integral from 0 to 6 of f(x) ?
The answer to integral from 0 to 6 of f(x) is f*18