What is the integral of e^{t/(RC)} ?

The integral of e^{t/(RC)} is CRe^{t/(CR)}+C

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integral of e^{t/(RC)}

\int e^{\frac{t}{RC}} d t

CR e^{\frac{t}{CR}} + C

Solution steps

\int e^{\frac{t}{RC}} d t

Apply u-substitution

: \int e^{u} CR d u

= \int e^{u} CR d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= CR \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= CR e^{u}

Substitute back

u = \frac{t}{CR}

= CR e^{\frac{t}{CR}}

Add a constant to the solution

= CR e^{\frac{t}{CR}} + C

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What is the integral of e^{t/(RC)} ?
The integral of e^{t/(RC)} is CRe^{t/(CR)}+C