What is the integral of (9sin(x)) ?

The integral of (9sin(x)) is -9cos(x)+C

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integral of (9sin(x))

\int (9 sin (x)) d x

- 9 cos (x) + C

Solution steps

\int 9 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 9 (- cos (x))

Simplify

= - 9 cos (x)

Add a constant to the solution

= - 9 cos (x) + C

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