What is the integral of (ln(x))/(x^{1.2)} ?

The integral of (ln(x))/(x^{1.2)} is -(5ln(x))/(x^{0.2)}-(25)/(x^{0.2)}+C

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integral of (ln(x))/(x^{1.2)}

\int \frac{ln ( x )}{x ^{1.2}} d x

- \frac{5 ln ( x )}{x ^{0.2}} - \frac{25}{x ^{0.2}} + C

Solution steps

\int \frac{ln ( x )}{x ^{1.2}} d x

Apply Integration By Parts

: - \frac{5 ln ( x )}{x ^{0.2}} - \int - \frac{5}{x ^{1.2}} d x

= - \frac{5 ln ( x )}{x ^{0.2}} - \int - \frac{5}{x ^{1.2}} d x

\int - \frac{5}{x ^{1.2}} d x = \frac{25}{x ^{0.2}}

= - \frac{5 ln ( x )}{x ^{0.2}} - \frac{25}{x ^{0.2}}

Add a constant to the solution

= - \frac{5 ln ( x )}{x ^{0.2}} - \frac{25}{x ^{0.2}} + C

x \to - 1 lim (2 x + 2)

\int sin (x) \cdot ln (cos (x)) d x

f (x) = \frac{2 x}{( x ^{3} - 8 ) ^{2}}

cos (x^{4})

What is the integral of (ln(x))/(x^{1.2)} ?
The integral of (ln(x))/(x^{1.2)} is -(5ln(x))/(x^{0.2)}-(25)/(x^{0.2)}+C