What is the (-sin(3x)*3)^' ?

The (-sin(3x)*3)^' is -9cos(3x)

What is the first (-sin(3x)*3)^' ?

The first (-sin(3x)*3)^' is -9cos(3x)

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(- sin (3 x) \cdot 3)^{^{'}}

- 9 cos (3 x)

Solution steps

(- sin (3 x) \cdot 3)^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 (sin (3 x))^{^{'}}

Apply the chain rule:

cos (3 x) (3 x)^{'}

= cos (3 x) (3 x)^{'}

(3 x)^{'} = 3

= - 3 cos (3 x) \cdot 3

Simplify

= - 9 cos (3 x)

x \to \infty lim (\frac{( e ^{2 x} )}{x ^{2}})

\frac{d y}{d x} = \frac{x}{y} + \frac{y}{x}

\frac{\partial}{\partial x} ((x^{2} + 2 y^{2} + 3 z^{2}) e^{- (x^{2} + y^{2} + z^{2})})

\int e^{\frac{x ^{2}}{2}} x^{3} d x

y = \frac{2 x + 3}{x}