en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=3+e^{-2t}

Solution

y^{^{'}} = 3 + e^{- 2 t}

Solution

y = 3 t - \frac{1}{2} e^{- 2 t} + c_{1}

Solution steps

y^{'} (t) = 3 + e^{- 2 t}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int 3 + e^{- 2 t} d t

\int 3 + e^{- 2 t} d t = 3 t - \frac{1}{2} e^{- 2 t} + c_{1}

y = 3 t - \frac{1}{2} e^{- 2 t} + c_{1}

Popular Examples

laplacetransform t^2sin(4t)laplace transform

t^{2} sin (4 t)

(dy)/(dt)+e^ty=12e^t

\frac{d y}{d t} + e^{t} y = 12 e^{t}

derivative of x/7+7/x derivative of

\frac{x}{7} + \frac{7}{x}

inverse oflaplace F(s)=(s+9)/(s^2-2s-3)inverse laplace

F (s) = \frac{s + 9}{s ^{2} - 2 s - 3}

integral of (sin(θ))

\int (sin (θ)) d θ

Frequently Asked Questions (FAQ)

What is the solution for y^'=3+e^{-2t} ?
The solution for y^'=3+e^{-2t} is y=3t-1/2 e^{-2t}+c_{1}