What is the integral of sqrt(5x+4) ?

The integral of sqrt(5x+4) is 2/15 (5x+4)^{3/2}+C

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integral of sqrt(5x+4)

\int 5 x + 4 d x

\frac{2}{15} (5 x + 4)^{\frac{3}{2}} + C

Solution steps

\int 5 x + 4 d x

Apply u-substitution

: \int \frac{u}{5} d u

= \int \frac{u}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{5} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 5 x + 4

= \frac{1}{5} \cdot \frac{2}{3} (5 x + 4)^{\frac{3}{2}}

Simplify

\frac{1}{5} \cdot \frac{2}{3} (5 x + 4)^{\frac{3}{2}} : \frac{2}{15} (5 x + 4)^{\frac{3}{2}}

= \frac{2}{15} (5 x + 4)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{15} (5 x + 4)^{\frac{3}{2}} + C

y = x^{4} - 3 x^{2} + 10, at x = 1

x \cdot y^{^{'}} = y + 2

\int (y^{2} + 4 y)^{2} d y

5 x^{3} + 2

What is the integral of sqrt(5x+4) ?
The integral of sqrt(5x+4) is 2/15 (5x+4)^{3/2}+C